m=62m^2

Solution for m=62m^2 equation:

m=62m^2

We move all terms to the left:

m-(62m^2)=0

determiningTheFunctionDomain
-62m^2+m=0

a = -62; b = 1; c = 0;
Δ = b2-4ac
Δ = 12-4·(-62)·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-1}{2*-62}=\frac{-2}{-124}
=1/62
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+1}{2*-62}=\frac{0}{-124}
=0
$